Math, asked by shivamindwar, 1 day ago

A and B can complete a work in 12 days, B and C in 15 days, and C and A in 20 days. In how many days will they complete the work a. together b. separately?​

Answers

Answered by bajrangiTiwari
0

Answer:

answer is 27

Step-by-step explanation:

15 plus 12=27

Answered by TheBestWriter
1

Solution:

Time taken by A and B together (A+B) to complete the work = 12 days

Time taken by B and C together (B+C) to complete the word = 15 days

Time taken by C and A together (C+A) to complete the work = 20 days

=> (A+B) 's one - day work = 1/12

=> (B+C) 's one - day work = 1/15

=> (C+A)'s one - day work = 1/20

a. To find the time taken by A,B and C if they work together we add to get, (A+B) 's one - day work + (B+C) 's one - day

+ (C+A)'s one - day work = 2(A+B+C) 's one - day work.

=> 2(A+B+C) 's one - day work = 1/12 + 1/15 + 1/20

= 5+4+3/60 = 12/60 = 1/5

=> (A+B+C) 's one - day work = 1/10

Thus, A,B and C together (A+B+C) will complete the work in 10 days.

b. A's one - day work = (A+B+C) 's one - day work -(B+C) 's one - day work

= 1/10 - 1/15 = (3-2/30) = 1/30

Thus, A alone will complete the work in 30 days.

B's one - day work = (A+B+C)'s one - day work

-(A+B)'s one - day work

= 1/10 - 1/12 = (6-5/60) = 1/60

Hence, C alone will complete the work in 60 days

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