A and b can complete a work in 12 days together, b and c can complete the same work in 15 days together and a and c can complete that work in 20 days together. in how many days a can complete the same work alone?
Answers
Complete the same work alone is :
A + B complete a piece of work in 12 days
B + C complete a piece of work in 15 days
C + A complete a piece of work in 20 days
First we take LCM of these numbers 12 , 15 , 20
so,
LCM is 60 ( total work is 60 )
A + B complete whole work in 12 days and total work is 60
then (A + B) complete work in 12 day = 60/12 = 5 (efficiency of A + B )
B + C complete whole work in 15 days and total work is 60
then ( B + C ) complete work in 15 day = 60/15 = 4 (efficiency of B+C )
C + A complete whole work in 20 days and total work is 60
then ( C + A ) complete work in 20 day = 60/20 = 3 (efficiency of C+A )
now ,
- Efficiency of ( A + B ) is 5
- Efficiency of ( B + C ) is 4
- Efficiency of ( C + A ) is 3
now , ( A + B ) + ( B + C ) + ( C + A ) = 5 + 4 + 3 = 12
A + B + B + C + C + A = 12
2A + 2B + 2C = 12
A + B + C = 12/2 = 6
Now , we know the efficiency of B + C = 4 , this value put in A + B + C ...
A + B + C = 6
A + 4 = 6
A = 2 (efficiency of A )
now , we know that C + A = 3
C + 2 = 3 ( A = 2 )
C = 1 (efficiency of C )
now , we know that B + C = 4
B + 1 = 4 ( C = 1 )
B = 13 (efficiency of B )
so , total work = 60
now, A complete whole work alone , 60/2 = 30 days
B complete whole work alone , 60/3 = 20 days
C complete whole work alone , 60/1 = 60 days
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