A and B can complete a work in 15 days and 10 days respectively. They started doing the work together but after 2 days B had to leave and A alone completed the remaining work. The whole work was completed in:
8 days
10 days
12 days
15 days
Answers
Answer:
♠ The correct option is C.
Step-by-step explanation:
♦ Let total work be 30 units (LCM of 10 and 15).
In one day, A can do 2 units of work and B can do 3 units of work.
In one day, both A and B can do 5 units of work.
In two days, A and B will complete 10 units of work. Remaining 20 units can be completed by A in 10 days (at rate of 2 units per day).
Hence, whole work will be completed in 12 days.
Answer:
12 days
Step-by-step explanation:
A and B can complete a work in 15 days and 10 days respectively.
Their 1 day work = (1/15 + 1/10) = 1/6
After 2 days B had to leave.
Work done in that 2 days = 1/6 * 2 = 1/3.
Remaining work = 1 - 1/3 = 2/3
A alone completed the remaining work.
=> 15 * 2/3
=> 10 days
Hence, total time taken = 12 days.
#Hope my answer helped you!