Math, asked by pviper416, 2 months ago

A and B can complete a work in 15 days and 10 days respectively they started doing the work together but after 2 days B had to leave and A alone complete the remaining work. the whole work completed in? ​

Answers

Answered by bson
1

Step-by-step explanation:

b does a work in 10 days

b does 1/10 work in 1 day

in 2 days

b does 2/10 work =1/5

remaining = 1-1/5 = 4/5

a does work in 15 days

a does 1/15 work in 1 day

a does 4/5 work in

1÷1/15 = x÷4/5

15×4/5 =x = 12 days

a stayed from start till work is done. so total no of days taken to finish work =12 days

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