Question

A and B can complete a work in 2 and 6 days respectively if C alone can complete the work in 3 days in how many days can they complete same work if all the three work together​

Answer 1

Answer:

1 day

Step-by-step explanation:

1/x = 1/2 + 1/6 + 1/3

1/x = (3+1+2)/6

1/x = 1 => x = 1 day

OR

let T.W = L.C.M(2,6,3) = 6 units

A => 6/2 = 3 units/day

B => 6/6 = 1 units/day

C => 6/3 = 2 units/day

together => 3+2+1 = 6 units/day

together can finish in= 6/6 = 1 day

Answer 2

Step-by-step explanation:

lcm of A,B, and C

or

lcm of 2,6and 3= 6

now find one day work

3/6,=2

6/6=1

2/6=3

sum of one day work

2+1+3=6

now this six is divided by six because six is our lcm

so 6÷6 = 1

if they were all together the work =1 days

this is our solution