Question

A and B can complete a work in 30 days both worked together for 10 days and after that finished the rest in next 10 days with help of C. If 3 days work of B is equal to 2 days work of C, then in how many days A can finish it alone
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Answer 1

Answer:

A+B's 20 day's work=

30

1

×20=

3

2

Remaining work=1−

3

2

=

3

3−2

=

3

1

Now,

3

1

rd

work is done by A in 20 days.

∴ The whole work will be done by A in 20×3=60 days.