Question

A and B can complete the work individually in 12 days and 18 days. they started doing the work together but after 4 days A had to leave and B alone completed the remaining work.the whole work was completed in

Answer 1

Answer:

12

Step-by-step explanation:

4/12 +x/18 =1

after lcm

6+x

___ =1

18

6+x=18

x=12

Answer 2

Answer:

Step-by-step explanation:

It is given that A can complete the work individually in $12$ days

B can complete the work individually in $18$ days

Units of work is calculated by finding the LCM

LCM of $12,18$ is $36$

There are $36$ units of work.

Efficiency of A $=36/12=3$units

Efficiency of B $=36/18=2$ units

Both can complete $3+2=5$ units is a day when work together.

They work together for $4$ days $=5*4=20$ units

Remaining units $=16$

It is done by B only.

As B's efficiency is $2$, it is done in $8$ days.

Work is completed in $4+8=12$ days.

#SPJ2