Math, asked by krushnachnagul, 4 months ago

A and B can complete work together in 5 days.
IfA works at twice his speed and B at half of his​

Answers

Answered by tajmohamad7719
4

Answer:

ANSWER

Let A's one day work be

x

1

and B's one day work

y

1

.

It is given that A and B can complete work together in 5 days, therefore, we have:

A+B=

x

1

+

y

1

=

5

1

xy

y

+

xy

x

=

5

1

xy

y+x

=

5

1

⇒5(x+y)=xy.....(1)

A worked at twice his speed means

x

2

B worked at half of his speed means

2y

1

Together they complete work in 4 days, therefore, we have:

x

2

+

2y

1

=

4

1

2xy

4y

+

2xy

x

=

4

1

2xy

4y+x

=

4

1

⇒4(x+4y)=2xy

⇒2(x+4y)=xy

⇒2x+8y=xy.....(2)

Substitute equation 2 in 1:

5x+5y=2x+8y

⇒5x−2x=8y−5y

⇒3x=3y

⇒x=y

x=y means that number of days worked by A alone is equal to B alone.

Now, substitute the value in equation 1:

x

1

+

x

1

=

5

1

x

1+1

=

5

1

x

2

=

5

1

⇒x=5×2

⇒x=10

Hence, it would take 10 days for A alone to complete the job.

Step-by-step explanation:

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Answered by anwarkhan22
1

Answer:

Hiii

Step-by-step explanation:

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