Question

A and b can do a job 10days,5 days respectively. They work together for 2 days. After which b was replace by c.. They can finish next 3 days.. How many days c alone can do 60 percent of the work

Answer 1

Answer:

3 days and 14 hours and 24 minutes

Step-by-step explanation:

speed of A = 1/10

Speed of B = 1/5

joint speed = 1/10+1/5 = 3/10

in tow days they do : 3/10x2= 3/5 job

job left after two days = 1-3/5 =2/5

joint speed of A+C = 2/5/ 3= 2/15

speed of C alone = 3/10-2/15 = 1/6

C takes for 1 job 6 day

for 60% job = 6 x 60% = 3.6 days = 3 days and 14 hours and 24 minutes