A and B can do a job in 10 days B alone can finish it in 15 days in how many days can a alone finish the job?
Answers
Answer:
most likely 15, their combined efforts shorten the time by 1/3, but that is not to say that either is more capable, it is just that the additional labor only shortens the time by a finite amount. there is no information that A or B is faster than the other by themselves, but cooperatively they can reduce the total time spent.
If both A and B can do in 10 days what each separately can complete in 15, then concurrently working A&B spend 15 days =2 pieces 30days=4
A &B working cooperatively for 10 days = 1 pieces 30 days=3
in this instance the more efficient use of their labor is to work separately, side by side, or to each do only a part of the process, whichever is quicker at each function, and hand off their work for the other to complete, thus reducing the total time from 15 days to even shorter, so they could potentially complete 2 in 10 days, increasing productivity by 50% (from 4 to 6 in a month).
Or you could mechanized the whole process and just have them feed and offload a machine that makes 10 a day…..
Step-by-step explanation:
BRO PLZ...GIVE HEARTS
AND PLZZ..MAKE THIS ANS AS BRAINLIST ANSWER
AND
A's 1 day's work =
10
1
B's 1 day's work =
15
1
Ratio of wages of A and B =
10
1
:
15
1
=3:2
Answer:
5
Step-by-step explanation:
days taken for both =10 days,which is the average days taken between the two.Hence total days taken(for the 2nd condition)=20
So,x(days taken for A)+y(days taken for B)=20
=>x+15=20
=>x=20-15
=>x=5