Question

A and B can do a job in 15 days. They work together for 6 days and then B leaves. If A can
do the job alone in 50 days, how long will he take to complete the unfinished job?​

Answer 1

Answer:

4.5 days

Step-by-step explanation:

A and B can do a job in 15 days.

so, job of B = B/15.

now, job of A = A/15.

So, by adding both.

$= > \: \frac{b}{15} + \frac{a}{15}$

$= > \: \frac{b \: + a}{15}$

so, total days consume by alone A = 50 days.

then,

$= > \: \frac{b \: \: + \: a}{15} = 50$

by cross multiplies; we get,

B + A = 50 × 15.

B + A = 750.

now subtracting a/15 from 750.

then;

$= > \: 750 - \frac{a}{15}$

$= > \: \frac{50 - 15a}{15}$

a = 4.5 days.

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Answer 2

Answer:

a and b can do the job in 1 day 1/15 part

a and b can do the job in 6 days 1/15*6=6/15

the unfinished part of the job=1-6/15=9/15

a can do the job in 50 days =9/15*50

=30 days (ans)