A and B can do a job in 16 days and 12 days respectively. B
has started the work alone 4 days before finishing the job, A
joins B. How many days has B worked alone?
(a) 6 days
(b) 4 days
(c) 5 days
(d) 7 days
() None of these
Answers
Answer:
He works only for 6days.
Step-by-step explanation:
Because 12-4 is 8days.
✤✤✤✤✤✤✤ Question ✤✤✤✤✤✤✤
A and B can do a job in 16 days and 12 days respectively.
B has started the work alone.
4 days before finishing the job, A joins B. How many days has B worked alone?
(a) 6 days
(b) 4 days
(c) 5 days ✔✔
(d) 7 days
(e) None of these
✤✤✤✤✤✤✤ Solution ✤✤✤✤✤✤✤
time taken by A to do the job= 16 days
so,
work done by A in one day = 1 / 16
time taken by B to do the job= 12 days
so,
work done by B in one day = 1 / 12
Now
Let, total no. of days
for which B worked = x days
then,
total work done by B = x ( 1/12) = x /12
It is given that,
No. of days for which A worked = 4 days
then,
total work done by A = 4 (1/16) = 4/16=1/4
So,
( x / 12 ) + ( 1 / 4) = 1
taking LCM
( x + 3 ) / 12 = 1
cross multiplting
x + 3 = 12
x = 12 - 3
x = 9 days
Therefore,
total no. of days for which B worked = 9 days
so,
no. of days in which B worked alone = 9 - 4
no.of days for which B worked alone=5days
Therefore,
the correct answer of this question is