A and b can do a job in 25 days.after 15 days of working together , b leaves . if a completed a remaining part of job in 20 days,how long would each take to complete the job seprately
Answers
Answered by
65
one day work=1/25
for 15 days=15/25=3/5
remaining work=1-3/4=2/5
A finish the 2/5work in 20 days
A/5=10
A=50
1/A+1/B=1/25
1/B=1/25-1/50
B=50
for 15 days=15/25=3/5
remaining work=1-3/4=2/5
A finish the 2/5work in 20 days
A/5=10
A=50
1/A+1/B=1/25
1/B=1/25-1/50
B=50
Answered by
11
Thank you for asking this question. Here is your answer:
Suppose total work is 1
A=1/15 & B=1/25 for one day work
when both work together
(A+B)= (1/15)+(1/25)=7/60
for 7 days
(7/60)x7=7/15
For remaining work
1-(7/15)=8/15
Answer (8/15)
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