A and B can do a job in 6 days ,B and C in 9 days and A and C in 12 days.How much time will they take to complete the job if they all work together.How long will each of them take to do the job ?
Answers
Answer:
72/13 days for 3 altogether
In 6 days, A+B completes whole work
In 1 day, A+B completes 1/6 work
In 9 days, B+C completes whole work
In 1 day, B+C completes 1/9 work
In 12 days, A+C completes whole work
In 1 day, A+C completes 1/12 work
Adding the three equations we get 2 day work of A, B, C = 2 (A+B+C)
= 1/6 + 1/9 + 1/12
= 6+4+3/36 = 13/36
Hence, 1 day's work = ½ of 13/36 = 13/72
Thus C does (13/72)-(1/6) = (13/72)–(12/72) =(1/72)th of the work in a day. So C will do the job in 72 days, working alone.
Thus A does (13/72)-(1/9) = (13/72)–(8/72) =(5/72)th of the work in a day. So A will do the job in 72/5 =14 and 2/5 days, working alone.
Thus B does (13/72)-(1/12) = (13/72)–(6/72) =(7/72)th of the work in a day. So A will do the job in 72/7 =10 and 2/7 days, working alone.
A takes 14 2/5 days; B takes 10 2/7 days and C takes 72 days , each working alone.
1/A + 1/B + 1/C = 13/72
1 / 1/A + 1/B + 1/C = 72/13 days for all 3 together
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Answer:
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