A and B can do a job together in 12 days. If A is 2 times as efficient as B, then how many days shall B alone take to complete the work?
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If they can finish together in 12 days, then:
1/A + 1/B=1/12
Since A is twice efficient as B, then 1/A=2/B. So:
2/B + 1/B=1/12
3/B=1/12
B=36
A=B/2=18
A takes 18 days alone to finish; B takes 36 days alone to finish
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