A and B can do a peice of work in 12 days A and C can do that work in 15 days B and C can do that work in 10 days so in how many days does A alone will do that work alone
Answers
Step-by-step explanation:
A B = 12 days
A C = 15 days
Both A and B can do that work in 12 days
Then A can do that in 6 ( half of 12) A = 6
Both A and C can do that in 15 days
Then A can do that in 7 1/2 days ( half of 15 ) A = 7 1/2
A = 6 + 7 1/2 = 13 1/2
A can do that work in 13 and half days ( 13 1/2 )
Answer:
no of days A and B do the work = 12
no. of days A and C do the work = 15
no. of days B and C do the work = 10
Work done by A and B in one day = 1/12
Work done by A and C in one day = 1/15
Work done by B and C in one day = 1/10
Adding all 2 (A+B+C) in one day = 1/12+1/15+1/10
= 5+4+6/60
=15/60
=1/4
A's one day work = (A+B+C) 1days - (B+C) 1days.
= 1/4 - 1/10
= 3/20