Question

A and b can do a pice a piece of work in 5 days b and c can do a picec of work in 7 days a and c can do a picece of work in 4 days

Answer 1

Let us assume that A, B, and C are completing aa, bb, and cc task everday and total task to be completed is 'ww'. So as per given problem statement:

3a+3b=w3a+3b=w ………(1

4b+4c=w4b+4c=w ………(2

4c+4a=w4c+4a=w ………(3

Now, we have to find out the no of days C will take to complete the 'ww' task. So, from above equations:

4∗((1/3)∗(w−3/4∗(w−4c)))+4c=w4∗((1/3)∗(w−3/4∗(w−4c)))+4c=w

(1/3)∗(w/4+3c)+c=w/4(1/3)∗(w/4+3c)+c=w/4

w/12+2c=w/4w/12+2c=w/4

2c=w/4−w/122c=w/4−w/12

2c=w/62c=w/6

12c=w12c=w

c=w/12c=w/12

It means that C complete 1/12 of task in one day, will take 12 days to complete the ‘w’ task.

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