A and B can do a picee of work in 30 days,while B and C can do the same work 24 days C and A in 20 days.if they all togther, in how many days will the work finish.
Answers
Answer:
18 days will the work finish, If they work together.
Step-by-step explanation:
Given that :
A and B can do a piece of work in 30 days :
C and B can do the same work 24 days
[tex]\sf \implies \dfrac{1}{b} + \dfrac{1}{c} = \dfrac{1}{24} [/tex]
C and A can do the same work in 20 days :
We have three equations now,
[tex]\sf 2. \implies \dfrac{1}{b} + \dfrac{1}{c} = \dfrac{1}{24} [/tex]
Add these equations :
⇒ 2(1/a +1/b + 1/c) = 1/30 + 1/24 + 1/20 = (20+25+30)/600 = 75/600 = 1/8
⇒ 1/a + 1/b + 1/c = 1/16
When A, B and C work together
The amount of work done in one day is 1/16
⇒ (1/a + 1/b + 1/c) - (1/b + 1/c) = 1/16 - 1/24 = (3–2)/48 = 1/48
⇒ 1/a = 1/48
The work done by A in one day = 1/48
As we know :
A, B & C work together for 10 days,
Work done by them together for 10 days :
⇒ 10 * (1/16) = 10/16 = 5/8
The remaining work to be done by A alone :
⇒1 - 5/8 = 3/8
The number of days taken by A alone to complete the remaining work :
⇒ (3/8)/(1/48) = 18 days.
Hence, 18 days is the answer.
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