Math, asked by mokshithreddy61, 1 day ago

A and B can do a piece of work in 10 days.A can do this work alone 15 days alone.how many days B can do alone​

Answers

Answered by akilabdulwadud
0

In 10 days A + B can so = 1 work

In 1 day A+B can do = 1/10 work

In 15 days A can do = 1 work

In 1 day A can do = 1/15 work

Let in x days B can do = 1 work

so in 1day B can do 1/x work

In 1 day A+B can do = 1/10 work

1/15 + 1/x = 1/10

1/x = 1/10 - 1/15

1/x = 1/30

x = 30

Hence B can finish the work in 30 days

Step-by-step explanation:

Answered by aditiinehraa
0

Step-by-step explanation:

In 10 days A + B can so = 1 work

In 1 day A+B can do = 1/10 work

In 15 days A can do = 1 work

In 1 day A can do = 1/15 work

Let in x days B can do = 1 work

so in 1day B can do 1/x work

In 1 day A+B can do = 1/10 work

1/15 + 1/x = 1/10

1/x = 1/10 - 1/15

1/x = 1/30

x = 30

Hence B can finish the work in 30 days

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