Question

A and B can do a piece of work in 10 days, B and C can do it in 16days and A and C can do it in 12 days. How long will each of them take to do the same work separately?
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Answer 1

Step-by-step explanation:

24 days

(A + B)’s 1 day’s work = \frac{1}{10}

(B + C)’s 1 day’s work = \frac{1}{12}

(C + A)’s 1 day’s work = \frac{1}{15}

On adding,

2(A + B + C)’s 1 day’s work = \frac{1}{10}+\frac{1}{12}+\frac{1}{15} = \frac{6+5+4}{60} = \frac{1}{4}

∴ (A + B + C)’s 1 day’s work = \frac{1}{8}

∴ A’s 1 day’s work = \frac{1}{8}-\frac{1}{12} = \frac{3-2}{24} = \frac{1}{24}

∴ A alone will complete the work in 24 days.