A and B can do a piece of work in 10 days B and C in 15 days and C in 25 days. They all work together for 4 days. A then leave and B and C go on together for 5 days and then B leaves; in how many days will C complete the work?
Answers
Step-by-step explanation:
The part of work A and B can do in aday is 1/10
The part of work B and C can do in aday is /15
1hecpart I of work C and Ai can do in aday i is 1/20
They all worked for 6days
So the part of work the all can do in aday is
2 (A + B+C ) Can do part of the work 1/10+1/20+ 1 /15 =( 6+3+4)/60 =13/60
So (A+B+C )Can do a part of the work in a day is 13/120
In 6 days they cover 6 ×13 /120
= 13/20
Balance of work is 1-- 13/20 =7/20
B and C together do part of work is day is 1/15
In 4 days B and C do part of WORK is 4/15
B LEAVES
BALANCE OF WORK =7/20 --4/15
=21-- 16 /60 =
5/60
=1/12
C HAS TO COMPLETE THE WORK OF 1/12
No of days C needs to complete the work is
1/12 /120 = 1/12 × 120 =10 days
C COMPLETES THE WORK IN 10 DAYAS.
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