A and b can do a piece of work in 10 days. B and c in 15 days. C and a in 20 days. All of them work at it for 2 days, then a leaves. After 2 days of this, b also leaves. C will complete rest of the work in how many days?
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Answer: 6.6667 Days
Step-by-step explanation:
Time Taken by A and B To complete work = 10 days
Work done by A and B in 1 day = 1/10 of Total Work
⇒ A + B = 1/10 --- (i)
Similarly Work Done by C and A in 1 day = 1/20 of total work
⇒ C+A=1/20---(ii)
Similarly Work Done by A, B and C in 1 day = 1/2 of total work
⇒ A+B+C = 1/2---(iii)
(iii)-(i)⇒A+B+C-(A+B)=(1/10)+(1/20)
⇒C =(2+1)/20)
⇒C = 3/20
Work Done C in 1 day = 3/20 of total work
⇒Time Taken by C to Complete Total Work = 20/3 Days = 6.667 Days
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