Question

A and B can do a piece of work in 10 hours B and C in 12 hours and C and A 15 hours how long will it take if the work together how long will it take to complete the work independently​

Answer 1

(A+B)'s one day work = 1/10

(B+C)'s one day work=1/12

(C+A)'s one day work=1/15

ATQ,

(A+B)(B+C)(C+A)=2(A+B+C)

WE have to find (A+B+C)

Therefore;

2(A+B+C)=1/10+1/12+1/15

2(A+B+C)=6+5+4/60

2(A+B+C)=15/60

(A+B+C)=15/60 X 2

(A+B+C)=1/2[IN LOWEST TERMS]