A and B can do a piece of work in 12 days and A alone can do it in 20 days. In how many days can B alone do it ?
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Answer:
A and B can do a piece of work in 12 days
A alone can do it in 20 days
B alone do it in (12×20/20-12) days=(12×20/8) days=30 days
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Step-by-step explanation:
20 days
A’s 1 day’s work = \frac{1}{12}-\frac{1}{30} = \frac{5-2}{60} = \frac{3}{60} = \frac{1}{20}
So, A alone will complete the work in 20 days.
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