A and B can do a piece of work in 12 days. B and C can do in 15 days. Com and A in 20 days. How long would A separately to do the same work
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ABC do work in 1day =1/12
A+B =1/12
B and C do work =1/15
B+C= 1/15
C+A=1/20
A+B = 1/12
B+C= 1/20.
(add together)
A-C =1/12 -1/15 (LCM 12 and 15 )
5-4/60 = 1/60
A+C = 1/20
A+B= 1/20 + A- C = 1/16
(add together)
2A = 1/16 + 1/60
3+1/60=1/15
2A=1/15
A=1/15 × 2 = 1/30
=30 days
A+B =1/12
B and C do work =1/15
B+C= 1/15
C+A=1/20
A+B = 1/12
B+C= 1/20.
(add together)
A-C =1/12 -1/15 (LCM 12 and 15 )
5-4/60 = 1/60
A+C = 1/20
A+B= 1/20 + A- C = 1/16
(add together)
2A = 1/16 + 1/60
3+1/60=1/15
2A=1/15
A=1/15 × 2 = 1/30
=30 days
ikbalHasim:
thanks
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