A and B can do a piece of work in 12 days B and C can do it in 15 days while C and A can finish it 20 days. in how many days will A,B,C finish it, working together? in how many days will each one of them finish it working alone?
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Answered by
6
Answer:
T-10 ,alone ->30,20,60
Step-by-step explanation:
T.W = L.C.M(12,15,20) = 60 units
their efficiency,
a+b--> 60/12 = 5 units/day
b +c=>60/15 = 4 '" "
c + a =>60/20 = 3 " "
(a+b+c) =12/2 = 6 units/day
a alone => 2u/day & b alone=> 3u/day
& c alone 1u/day
together = 60/6 = 10 days
separately a = 60/2 = 30 days
& b = 60/3 = 20 days & c=60/1 = 60 days
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