Question

A and B can do a piece of work in 12 days B and C can do it in 15 days while C and A can finish it 20 days. in how many days will A,B,C finish it, working together? in how many days will each one of them finish it working alone?​

Answer 1

Answer:

.. ........................

..

Answer 2

Answer:

T-10 ,alone ->30,20,60

Step-by-step explanation:

T.W = L.C.M(12,15,20) = 60 units

their efficiency,

a+b--> 60/12 = 5 units/day

b +c=>60/15 = 4 '" "

c + a =>60/20 = 3 " "

(a+b+c) =12/2 = 6 units/day

a alone => 2u/day & b alone=> 3u/day

& c alone 1u/day

together = 60/6 = 10 days

separately a = 60/2 = 30 days

& b = 60/3 = 20 days & c=60/1 = 60 days