Question

A and B can do a piece of work in 12 days; B and C can do it in 15 days while C and A can finish it in 20 days. If A, B, C works together, in how many days will they finish the work? In how many days will each one of them finish it, working alone?​

Answer 1

Answer:

Step-by-step explanation:

A + B = 12

B + C = 15

C + A = 20

A DIVIDED BY B = 6

B IS DIVIDED BY C = 6

C DIVIDED BY A =10

10+6+6=22

Answer 2

Answer:

Work done by A and B in 1 day=1/12 <br> Work done by B and C in 1 day=1/15 <br> Work done by C and A 1 day=1/20 <br> Adding all the three, we get, work done by <br>

in 1 day=

<br>

A,B and C can together finish 1/10th of the work in 1 day. <br>

Work done by A in 1 day=Work done by A,B and C in 1 day-Work done by B and C in 1 day

<br>

A alone can do it in 30 days. <br> Work done by B in 1 day=

<br>

B alone can do it in 20 days. <br> Work done by C in 1 day

<br>

C alone can do it in 60 days.

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