Math, asked by chiranjeebsonowal17, 11 months ago

A and B can do a piece of work in 12 days.B and C can do it in 15 days while C and A can finish it in 20 days . In how many days A and B finish it,working together.in how many days will each of them finish it working alone?


gujjarankit: a,b,c altogether complete the whole work in 10 days. A alone complete the work in 30 days
gujjarankit: B alone complete the work in 20 days

Answers

Answered by Blaezii
6

Answer:

A+B = 12  

B+C = 15

A+C = 20

Lcm of (12,15,20) = 60

Efficiency is  

A+B = 5  

B+C = 4

A+C = 3

Total efficiency

2 (A+B+C) = 12  

A+B+C = 6

Individual efficiency

A = 6 - 4 = 2  

B = 6 - 3 = 3  

C = 6 - 5 = 1

Individual time taken

A = 60/2 = 30 days

B =60/3 = 20 days  

C = 60/1 = 60 days

Answered by gujjarankit
1

maybe it is also helpful ...hopefully

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