A and B can do a piece of work in 12 days, B and C can do the work in 15 days, while C and A can do it in 20 days. Find how long will they take, working together, to complete the work?
Answers
Answer:
Always go with the LCM method, as answer can be calculated while the first reading of the question as the calculation involves integers instead of fractions and they are easily handled.
LCM(12,15,20)=60
Now this 60 units can be treated as the total work and we will now calculate the one day work
One day work of A and B = 60/12 = 5 units
One day work of B and C = 60/15 = 4 units
One day work of C and A = 60/20= 3 units
Now if we add all three we get:-
2(A+B+C)=12 units
So one day work of A, B and C put together is 12/2 = 6 units
To find one day work of A:-
One day work of A, B and C together minus one day work of B and C, that is 6–4=2 units
If the total work is of 60 units and the one day work of A is 2 unit, then alone A needs 60/2 = 30 days to finish the work.
The same way we can find the number of days required by B and C to finish the work by themselves.
Believe me, every question on time and work can be solved with this method and it's really a time saver in exams and involves less calculation
Step-by-step explanation:
Answer:
According to questions,
A worked for 5 days and
B worked for 7 days
If A and B Work together for 5 days
they would complete 4×5=20 units
remaining work = 48−20
=28 units
Now B has to work for 2 more days and if he does it along
with C for 2 days. Then, both would complete (3×2)=6
units of work.
work left = 28−6=22 units
Now C completes in 13−2=11 days
So, C works2211 = 2 units / day
(efficiency) and B+Cdoes 3 units / day (efficiency)
So B does 1 unit/day
B will complete the whole work in 481= 48 days
Step-by-step explanation:
HOPE YOU LIKED THE ANSWER THEN PLEASE MAKE ME AS BRAINLEST PLEASE