A and b can do a piece of work in 12 days b and c in 15 days c and a in 20 days.in how many days can a alone do it
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a+b=12
b+c=15
c+a=20
lcm=60
efficiency:: a+b=5
b+c=4,c+a=3
add efficiency
(a+b+c)×2=5+4+3=12
(a+b+c)=6
but efficiency of b+c
we get a=2
so days for a=60/2=30days
b+c=15
c+a=20
lcm=60
efficiency:: a+b=5
b+c=4,c+a=3
add efficiency
(a+b+c)×2=5+4+3=12
(a+b+c)=6
but efficiency of b+c
we get a=2
so days for a=60/2=30days
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