A and b can do a piece of work in 12 days, b and c in 15 days, c and a in 20 days. How long would it take for 'c to do the same work alone? 55 days 50 days 56 days
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A and B can do work (A+B) = 12
B and C can do work (B+C) = 15
A and C can do work (A+C) = 20
L.c.m of (12,15,20) = 60
Efficiency is
A+B = 5
B+C = 4
A+C = 3
Total efficiency
2 (A+B+C) = 12
A+B+C = 6
Individual efficiency
A = 6 - 4 = 2
B = 6 - 3 = 3
C = 6 - 5 = 1
Individual time taken
A = 60/2 = 30 days
B =60/3 = 20 days
C = 60/1 = 60 days
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@GauravSaxena01
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