Math, asked by aishuaishaishu8072, 1 year ago

A and b can do a piece of work in 12 days, b and c in 15 days, c and a in 20 days. How long would it take for 'c to do the same work alone? 55 days 50 days 56 days

Answers

Answered by GauravSaxena01
0

Answer:

A and B  can do  work  (A+B) = 12  

B and C can do work (B+C) = 15

A and C  can do work (A+C) = 20

L.c.m of (12,15,20) = 60

Efficiency is  

A+B = 5  

B+C = 4

A+C = 3

Total efficiency

2 (A+B+C) = 12  

A+B+C = 6

Individual efficiency

A = 6 - 4 = 2  

B = 6 - 3 = 3  

C = 6 - 5 = 1

Individual time taken

A = 60/2 = 30 days

B =60/3 = 20 days  

C = 60/1 = 60 days

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@GauravSaxena01

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