A and B can do a piece of work in 12 days, B and C in 15days, and C and A in 20 days . How much time will A alone take to finish the job?
Answers
Answered by
0
Answer:
10 days will be answer
Step-by-step explanation:
Since we have given that
Number of days in which A and B can do a piece of work = 12 days
Number of days in which B and C can do a piece of work = 15 days
Number of days in which C and A can do a piece of work = 20 days
L.C.M of 12, 15, 20 = 60
Number of units done by A and B = \dfrac{60}{12}=5
12
60
=5
Number of units done by B and C = \dfrac{60}{15}=4
15
60
=4
Number of units done by C and A = \dfrac{60}{20}=3
20
60
=3
Number of days all A, B and C take together is given by
\begin{gathered}\dfrac{60\times 2}{5+4+3}\\\\\\=\dfrac{120}{12}\\\\=10\end{gathered}
5+4+3
60×2
=
12
120
=10
Similar questions