A and B can do a piece of work in 12 days. B and C in 16 days. After A alone worked on it for 5 days followed by B alone for 7 days, C finished in 13 days. In how many days can each do it separately, if they work alone?
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Answer:
A worked for 5 days and
B worked for 7 days
If A and B Work together for 5 days
they would complete 4×5=20 units
remaining work = 48−20
=28 units
Now B has to work for 2 more days and if he does it along
with C for 2 days. Then, both would complete (3×2)=6
units of work.
work left = 28−6=22 units
Now C completes in 13−2=11 days
So, C works2211 = 2 units / day
(efficiency) and B+Cdoes 3 units / day (efficiency)
So B does 1 unit/day
B will complete the whole work in 481= 48 day
Step-by-step explanation:
hope my answer help you
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