A and B can do a piece of work in 12 days,C and B can do in 20 days.In how many days will C can finished the work separately.
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A+B= 12
B+C= 20
TOTAL WORK= L.C.M OF 12,20= 240
EFFICIENCY OF-----
A+B = 20
B+C = 12
-------------
A+C = 32
---------------
2(A+B+C)= 64
A+B+C = 64/2= 32
efficiency of c = 32-20= 12
c = TW/ efficiency= 240/12 = 20 days will be the answer
B+C= 20
TOTAL WORK= L.C.M OF 12,20= 240
EFFICIENCY OF-----
A+B = 20
B+C = 12
-------------
A+C = 32
---------------
2(A+B+C)= 64
A+B+C = 64/2= 32
efficiency of c = 32-20= 12
c = TW/ efficiency= 240/12 = 20 days will be the answer
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A+B= 12
B+C= 20
TOTAL WORK= L.C.M OF 12,20= 240
EFFICIENCY OF-----
A+B = 20
B+C = 12
-------------
A+C = 32
---------------
2(A+B+C)= 64
A+B+C = 64/2= 32
efficiency of c = 32-20= 12
c = TW/ efficiency= 240/12 = 20 days will be the answer
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