Question

A and B can do a piece of work in 12 days while B and C can do the same in 16 days. A works for 5days, B works for 7 days and C works for 13 days to complete the work. how many days will C require to complete the total work alone?​

Answer 1

Answer: 24

Step-by-step explanation:

A+B=12

                LCM 48

B+C=16

EFFICIENCY OF A+B=4

                           B+C=3

A=5d B=7d C=13d

A+B works for 5 days Then total work = 4x5=20

B =7-5=2

B+C   = 3x2=6

C's remaining day =11

remaining work=48-(20+6)=22

c's efficiency =22/11=2

c completed the whole work in = 48/2= 24days