A and B can do a piece of work in 14 days and 21 days respectively they begin together and work at 6days then a left the job and B had to complete the remaining work alone in how many days was were completed​
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Answer:
12 days
Step-by-step explanation:
Work completed by A in 1 day=1/14
Work completed by B in 1 day=1/21
Work completed by A and B in 6 days=1/14+1/21*6=5/42*6=5/7
Work left = 1-5/7 =2/7
Days needed by B=(2/7)/(1/21)=6
Therefore total no. of days=6+6=12
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