Question

A.and b can do a piece of work in 15 and 18 days respectively .a work at it for 10 days and then b finish the remaining work .find the time taken by b to finish the remaining work

Answer 1

since A's 1 day work =1/18
work done by A alone in 10 days =1/18*10= 5/9
work done by A and B together =1-5/9=4/9
(A+B)'s 1 day work =1/15+1/18=11/90
No of days A and B worked together= 4/9/11/90=40/11

Hence A left work after 40/11 days