A and B can do a piece of work in 15 days. A alone can finish it in 20 days .How many days will be take to finish the same work?
Pls answer it as soon as possible..... pls
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A and B together can complete the work in 15 days, so (A+B)’s one day work = 1/15
If A alone can complete a work in 20 days then A's one day work =1/20
Let B alone can complete the work in x days , so B's one day work = 1/x
Now ,
(A+B)’s one day work = A’s one day work + B’s one day work
=> 1/15=1/20+1/x
=> 1/x= 1/15 - 1/20
=> 1/x = 1/60
=> x=60
Hence B alone can complete the work in 60 days
If A alone can complete a work in 20 days then A's one day work =1/20
Let B alone can complete the work in x days , so B's one day work = 1/x
Now ,
(A+B)’s one day work = A’s one day work + B’s one day work
=> 1/15=1/20+1/x
=> 1/x= 1/15 - 1/20
=> 1/x = 1/60
=> x=60
Hence B alone can complete the work in 60 days
AnshikaSharma9988:
tq soo much
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