A and B can do a piece of work, in 15 days and 20 days respectively
Find (i) The work done by A in 3 days
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A→ 20 days
B→ 15 days
Let us say. 60 unit work was there & C = x unit/Day.
A = 3 unit/Day
B=4 unit /Day.
A+B = 7×6=42 unit work done by A & B. left
(60-42) unit = 10 unit will be done by A&C
A+C=(3+x)×4=10⇒12+4x=10⇒x=46=2.5dayunit.
C Alone could do the work.
= 1.5unit/day6.0unit
= 40 day
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1/5th of work done in 15 days.!
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