Question

A and B can do a piece of work in 18 days; B and C can do it in 24 days, A and C can do it in 36 days. In how many days B alone can finish the work?

Answer 1

Answer:

A+B=1 / 18

B+C=1/24

A+C=1 / 36 Adding we get

2 A+2B+2C=1 /18+I/24 +1/36

2 A+2B+2C=4/72 +3/72 +2/72

2A+2B +2C=9/72 = I/8

A + B + C = (1/8) / 2 = I/16

B = (A+B+C)-A +C....( where A+C=1/36)

B=1/16 - I/36=9/I44-4/144

B=5/i44=28 4/5 days