A and B can do a piece of work in 18 days B and C can do it in 24 days and C can do it in 36 days in how many days will a b c finish it working together and separately
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Answer :-
A, B and C can do the same work in 12 days.
Solution :-
A and B can do a work in 18 days
So A and B one day work = 1/18
B and C can do it in 24 days
B and C one day work = 1/24
C can do it in 36 days
C's one day work = 1/36
We know that
B's one day work = B and C one day work - C's one day work
= 1/24 - 1/36
= (3 - 2)/72
= 1/72
B's one day work = 1/72
We know that
A's one day work = A and B one day work - B's one day work
= 1/18 - 1/72
= (4 - 1)/72
= 3/72
= 1/24
A's one day work = 1/24
We know that
A,B and C one day work = A's one day work + B's one day work + C's one day work
= 1/24 + 1/72 + 1/36
= (3 + 1 + 2)/72
= 6/72
A,B and C one day work = 6/72
A, B and C can do it in 72/6 = 12 days
So A, B and C can do the same work in 12 days.
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