Math, asked by jyothivbcops, 1 year ago

A and B can do a piece of work in 18 days B and C can do it in 24 days and C can do it in 36 days in how many days will a b c finish it working together and separately​

Answers

Answered by Anonymous
29

Answer :-

A, B and C can do the same work in 12 days.

Solution :-

A and B can do a work in 18 days

So A and B one day work = 1/18

B and C can do it in 24 days

B and C one day work = 1/24

C can do it in 36 days

C's one day work = 1/36

We know that

B's one day work = B and C one day work - C's one day work

= 1/24 - 1/36

= (3 - 2)/72

= 1/72

B's one day work = 1/72

We know that

A's one day work = A and B one day work - B's one day work

= 1/18 - 1/72

= (4 - 1)/72

= 3/72

= 1/24

A's one day work = 1/24

We know that

A,B and C one day work = A's one day work + B's one day work + C's one day work

= 1/24 + 1/72 + 1/36

= (3 + 1 + 2)/72

= 6/72

A,B and C one day work = 6/72

A, B and C can do it in 72/6 = 12 days

So A, B and C can do the same work in 12 days.

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