A and B can do a piece of work in 18 days, B and C can do it in 24 days while C and A can finish it in 36 days. In how many days will each one of them finish it working alone?
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Step-by-step explanation:
The work will be completed in 16 days
Answered by
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Step-by-step explanation:
A +B = 18
B + C = 24
C + A = 36
L.c.m of (A+ B) , ( B+C), (C+A) = 72 (total work)
efficiency of A+B = 72/18 = 4
B +C = 72/24 = 3
A+ C = 72/36 = 2
efficiency of (A+B+C) = (4+3+2)/2 =9/2
efficiency of A = 9/2 -3 =3/2
efficiency of B = 9/2 - 2 = 5/2
efficiency of C = 9/2 - 4 =1/2
Day for A = 72÷ (3/2) = 48 days
Day for B = 72 ÷ (5/2) = 28.8 days
Day for C = 72 ÷ (1/2) = 154 days
Day for (A+B+C) = 72 ÷(9/2) =16 days
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