A and B can do a piece of work in 18 days, B and C can do it in 24 days, A and C can do it in 36 days. In how many days will A, B and C finish it, working separately?
Answers
Step-by-step explanation:
In 1 days A and B can do 1/18 part
In 1 day B and C can do 1/24 part
In 1 day A and C can do 1/36 part
In 1 day A+B+B+C+A+C can do=(1/18+1/24+1/36) part
In 1 day 2(A+B+C) can do=(4+3+2)/72
In 1 day A+B+C can do =1/16 part
(A+B+C)-(A+B) 1 days work=1/16-1/18
C alone does (1/16)-(1/18) = (18–16)/(16*18) = 2/(16*18) = (1/144)th part of the work in a day.
So C, working alone, will complete the work in 144 days.
A alone does (1/16)-(1/24) = (24–16)/(16*24) = 8/(16*24) = (1/48)th part of the work in a day.
So A, working alone, will complete the work in 48 days.
B alone does (1/16)-(1/36) = (36–16)/(16*36) = 20/(16*36) = (5/144)th part of the work in a day.
So C, working alone, will complete the work in 144/5 days.
Step-by-step explanation:
A and B can do a piece of work in 18 days, B and C can do it in 24 days, A and C can do it in 36 days. In how many days will A, B and C finish it, working separately?