A and B can do a piece of work in 18 days, B and
C can do it in 24 days while C and A can finish it
in 36 days. In how many days can A, B, C finish it,
if they all work together?
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Answer:
A and B can do (1/18)th of the work in a day.
B and C can do (1/24)th of the work in a day.
A and C can do (1/36)th of the work in a day.
2A+2B+2C = (1/18)+(1/24)+(1/36)
= (4/72)+(3/72)+(2/72)
= (9/72) or
A+B+C = (9/144) = (1/16)th of the work in a day.
C alone does (1/16)-(1/18) = (18–16)/(16*18) = 2/(16*18) = (1/144)th part of the work in a day. So C, working alone, will complete the work in 144 days.
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