Question

A and B can do a piece of work in 18 days. B and C can do it in 24 days while C and A can
finish it in 36 days. In how many days can A, B, C finish it, if they all work together?​

Answer 1

Answer:

A and B one day work is 1/18

B and C one day work is 1/24

A and C one day work is 1/36

2(A+B+C) one day work is 1/18+1/24+1/36=1/6

A+B+C one day work is 1/12

A+B+C can do 1 work in 12 days

Answer 2

$\huge \underline \bold {Question}$

A and B can do a piece of work in 18 days. B and C can do it in 24 days while C and A can

finish it in 36 days. In how many days can A, B, C finish it, if they all work together?

$\huge \underline \bold {Required \: Answer}$

Given:-

☛(A+B) can do whole work in=18 days

☛(B+C) can do whole work in=24 days

☛(A+C) can do whole work in=36 days

LCM of 18,24 and 36=72 units=Let total work

So,

⇒Efficiency of (A+B)=72/18=4 units / day. [Equation 1]

⇒Efficiency of (B+C)=72/24=3 units / day. [Equation 2]

⇒Efficiency of (A+C)=72/36=2 units / day. [Equation 3]

By adding Equation 1 , 2 and 3,we get

⇒(A+B)+(B+C)+(A+C)=4+3+2

⇒2A+2B+2C=9

⇒2(A+B+C)=9

By dividing both sides by 2,we get

⇒(A+B+C)=(9/2) units / day

Hence,all three together will complete their work in =(72)/(9/2)=(72×2)/9=16 days

So,they three will complete their work together in 16 days altogether.

Hope it helps!!

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