Math, asked by akhilesh765432, 1 year ago

A and B can do a piece of work in 18 days; B and C in 24 days and A and C in 36 days what time can they do it, all working together?​

Answers

Answered by shettigopi2466
1

Answer:

A+B B+C C+A

18 24 36

72

4 3 2

(A+B+C) = 9/2 =4.5

A=1.5

B=2.5

C=0.5

Total work = 72/4.5 =16days

Answered by Anonymous
102

Answer:

Let they altogether can do work in x days.

\underline{\bigstar\:\textsf{According to the given Question :}}

:\implies\sf 2(A+B+C)=\dfrac{x}{18}+\dfrac{x}{24}+\dfrac{x}{36}=Work\\\\\\:\implies\sf (A+B+C)=\dfrac{1}{2} \bigg(\dfrac{x}{18}+\dfrac{x}{24}+\dfrac{x}{36} \bigg)=1\\\\\\:\implies\sf \dfrac{1}{2} \bigg(\dfrac{x}{18}+\dfrac{x}{24}+\dfrac{x}{36} \bigg)=1\\\\\\:\implies\sf \dfrac{4x + 3x+2x}{72} = 2\\\\\\:\implies\sf \dfrac{9x}{72} = 2\\\\\\:\implies\sf \dfrac{x}{8} = 2\\\\\\:\implies\sf x = 2 \times 8\\\\\\:\implies\underline{\boxed{\sf x = 16 \:Days}}

\therefore\:\underline{\textsf{In \textbf{16 Days} they can do it working altogether.}}

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