A and B can do a piece of work in 20/3 days. B and C together can do it in 120/13 days. If A is twice as good a workman as C, find in how many days B alone can do the work ?
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Given
A and B can finish the work = 18 days
Formula Used
Work = time × Efficiency
Calculation
Efficiency of A : B = 2 : 1
Total work = (A + B) × 18 = 3 × 18 = 54
So, A can do work alone in days = 54/2 = 27 days
∴ The work is to be done by A alone in 27 days
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