A and B can do a piece of work in 20 days .If A alone can do the whole work in 36 days in how many days will B finish the work alone
Answers
Answered by
0
Answer:
45 days
Step-by-step explanation:
LCM between 20 and 36 gives tota units of work - 180 Units
A + B per day - 180/20 - 9 Units
A per day -180/36- 5 Units
B per day - 9-5 - 4 units
No. of days - 180/4-45 days
Answered by
0
Answer:
Work done by A in 36 days = 1
work done by A in 1 day = 1/36
work done by A & B in 20 days = 1
work done by A&B in 1 day = 1/20
So work done by B in 1 day = 1/20-1/36= 1/45
Now, Time taken by B to complete 1/45 work = 1 day
so Time taken by B to complete 1 work = 1÷ 1/45 = 45 days
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