A and B can do a piece of work in 22 1/2days. B takes 24 days more than A to finish the work alone. A can finish the whole work in?
Answers
Answered by
0
let A takes x days to finish the whole work.
Expalaination:
---------------------
A 's 1 day's work = 1/ x
B 's 1 day's work = 1/ (x + 24)
(A + B)'s 1 day's work
1/ (22 1/2) = 1/45/2 = 2/ 45
1/ x + (1/ x + 24) = 2/ 45
x + 24 + x = x ( x + 24) × 2 / 45
45 (2x + 24) = 2x^2 + 48x
90x + 1080 = 2x^2 + 48x
2x^2 - 42x - 1080 = 0
2( x^2 - 21x - 540) = 0
x^2 - 21x - 540 = 0
x^2 - 36x + 15x - 540 = 0
x( x - 36) + 15( x - 36) = 0
(x - 36) ( x + 15) = 0
x = 36, - 15
neglec -15 , days can't count as -ve.
so take +ve value of x = 36
Answer:
--------------
A alone can finish the work in 36days
Expalaination:
---------------------
A 's 1 day's work = 1/ x
B 's 1 day's work = 1/ (x + 24)
(A + B)'s 1 day's work
1/ (22 1/2) = 1/45/2 = 2/ 45
1/ x + (1/ x + 24) = 2/ 45
x + 24 + x = x ( x + 24) × 2 / 45
45 (2x + 24) = 2x^2 + 48x
90x + 1080 = 2x^2 + 48x
2x^2 - 42x - 1080 = 0
2( x^2 - 21x - 540) = 0
x^2 - 21x - 540 = 0
x^2 - 36x + 15x - 540 = 0
x( x - 36) + 15( x - 36) = 0
(x - 36) ( x + 15) = 0
x = 36, - 15
neglec -15 , days can't count as -ve.
so take +ve value of x = 36
Answer:
--------------
A alone can finish the work in 36days
Similar questions