Question

A and B can do a piece of work in 24
days. A works for 8 days alone and
the remaining work is done by B alone
in 18 days. Find in how many days B
alone can complete 3 times the total
work working with 75% of efficiency?​

Answer 1

Answer:

Your answer is almost ready

Step-by-step explanation:

B does 1/24 of the work per day. Together, they do 1/8 + 1/24, or 3/24 + 1/24, or 4/24, or 1/6 of the work per day. So it will take them 6 days working together. A can do a piece of work in 10 days which B alone can do in 12 days.